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Mathematics
Class 92025–26 SNC25 Questions SolvedEnglish Medium

Exercise 2.2 — Class 9 Mathematics Solutions

All 25 questions below are worked step by step — every step clearly worked out with mathematical reasons — for the Punjab Board 9th class Mathematics textbook.

Exercise 2.2

3 Questions (22 Sub-parts)

Every solution is shown in full. Switch to Self-Test Mode to hide them and practice first.

Q1Question 1

Easy

Express each of the following in logarithmic form:

Q1Part (i)

EasyApproved by Miss Aniya • Aug 22, 2026

103=1000

Hint

Recall that ay=x⟺loga⁡x=y.

Solution

  1. State the definition of a logarithm.

    ay=x⟺loga⁡x=y
  2. Identify the base, exponent, and value.

    • Base: a=10
    • Exponent: y=3
    • Value: x=1000
  3. Write in logarithmic form.

    log10⁡1000=3

Answer

log10⁡1000=3

Q1Part (ii)

EasyApproved by Miss Aniya • Aug 22, 2026

28=256

Hint

Base is 2, exponent is 8, and value is 256.

Solution

  1. State the definition of a logarithm.

    ay=x⟺loga⁡x=y
  2. Identify the components.

    • Base a=2
    • Exponent y=8
    • Value x=256
  3. Convert to logarithmic form.

    log2⁡256=8

Answer

log2⁡256=8

Q1Part (iii)

EasyApproved by Miss Aniya • Aug 22, 2026

3−3=127

Hint

Base is 3, exponent is −3, and value is 127.

Solution

  1. State the conversion rule.

    ay=x⟺loga⁡x=y
  2. Identify the components.

    • Base a=3
    • Exponent y=−3
    • Value x=127
  3. Write in logarithmic form.

    log3⁡(127)=−3

Answer

log3⁡(127)=−3

Q1Part (iv)

EasyApproved by Miss Aniya • Aug 22, 2026

202=400

Hint

Base is 20, exponent is 2, and value is 400.

Solution

  1. State the conversion rule.

    ay=x⟺loga⁡x=y
  2. Identify the components.

    • Base a=20
    • Exponent y=2
    • Value x=400
  3. Write in logarithmic form.

    log20⁡400=2

Answer

log20⁡400=2

Q1Part (v)

EasyApproved by Miss Aniya • Aug 22, 2026

16−14=12

Hint

Base is 16, exponent is −14, and value is 12.

Solution

  1. State the conversion rule.

    ay=x⟺loga⁡x=y
  2. Identify the components.

    • Base a=16
    • Exponent y=−14
    • Value x=12
  3. Write in logarithmic form.

    log16⁡(12)=−14

Answer

log16⁡(12)=−14

Q1Part (vi)

EasyApproved by Miss Aniya • Aug 22, 2026

112=121

Hint

Base is 11, exponent is 2, and value is 121.

Solution

  1. State the conversion rule.

    ay=x⟺loga⁡x=y
  2. Identify components.

    • Base a=11
    • Exponent y=2
    • Value x=121
  3. Write in logarithmic form.

    log11⁡121=2

Answer

log11⁡121=2

Q1Part (vii)

EasyApproved by Miss Aniya • Aug 22, 2026

p=qr

Hint

Rearrange to qr=p. Base is q, exponent is r, and value is p.

Solution

  1. State the conversion rule.

    ay=x⟺loga⁡x=y
  2. Identify components.

    • Exponential equation: qr=p
    • Base a=q
    • Exponent y=r
    • Value x=p
  3. Write in logarithmic form.

    logq⁡p=r

Answer

logq⁡p=r

Q1Part (viii)

EasyApproved by Miss Aniya • Aug 22, 2026

(32)−15=12

Hint

Base is 32, exponent is −15, and value is 12.

Solution

  1. State the conversion rule.

    ay=x⟺loga⁡x=y
  2. Identify components.

    • Base a=32
    • Exponent y=−15
    • Value x=12
  3. Write in logarithmic form.

    log32⁡(12)=−15

Answer

log32⁡(12)=−15

Q2Question 2

Easy

Express each of the following in exponential form:

Q2Part (i)

EasyApproved by Miss Aniya • Aug 22, 2026

log5⁡125=3

Hint

Use the relationship: loga⁡x=y⟺ay=x.

Solution

  1. State the inverse definition.

    loga⁡x=y⟺ay=x
  2. Identify base, exponent, and value.

    • Base a=5
    • Exponent y=3
    • Value x=125
  3. Write in exponential form.

    53=125

Answer

53=125

Q2Part (ii)

EasyApproved by Miss Aniya • Aug 22, 2026

log2⁡16=4

Hint

Base is 2, exponent is 4, and value is 16.

Solution

  1. State the conversion rule.

    loga⁡x=y⟺ay=x
  2. Identify components.

    • Base a=2
    • Exponent y=4
    • Value x=16
  3. Write in exponential form.

    24=16

Answer

24=16

Q2Part (iii)

EasyApproved by Miss Aniya • Aug 22, 2026

log23⁡1=0

Hint

Any non-zero base raised to power 0 equals 1 (a0=1).

Solution

  1. State the conversion rule.

    loga⁡x=y⟺ay=x
  2. Identify components.

    • Base a=23
    • Exponent y=0
    • Value x=1
  3. Write in exponential form.

    230=1

Answer

230=1

Q2Part (iv)

EasyApproved by Miss Aniya • Aug 22, 2026

log5⁡5=1

Hint

Base is 5, exponent is 1, and value is 5.

Solution

  1. State the conversion rule.

    loga⁡x=y⟺ay=x
  2. Identify components.

    • Base a=5
    • Exponent y=1
    • Value x=5
  3. Write in exponential form.

    51=5

Answer

51=5

Q2Part (v)

EasyApproved by Miss Aniya • Aug 22, 2026

log2⁡(18)=−3

Hint

Base is 2, exponent is −3, and value is 18.

Solution

  1. State the conversion rule.

    loga⁡x=y⟺ay=x
  2. Identify components.

    • Base a=2
    • Exponent y=−3
    • Value x=18
  3. Write in exponential form.

    2−3=18

Answer

2−3=18

Q2Part (vi)

EasyApproved by Miss Aniya • Aug 22, 2026

12=log9⁡3

Hint

Base is 9, exponent is 12, and value is 3.

Solution

  1. Rewrite with logarithm on left-hand side.

    log9⁡3=12
  2. State the conversion rule.

    loga⁡x=y⟺ay=x
  3. Write in exponential form.

    912=3

Answer

912=3

Q2Part (vii)

EasyApproved by Wasif • Aug 25, 2026

5=log10⁡100000

Hint

By definition of logarithm, loga⁡x=y⟺ay=x. Here base a=10, exponent y=5, and number x=100,000, giving 105=100,000.

Solution

  1. Understand the definition of a logarithm.

    By the fundamental definition of a logarithm:

    loga⁡(x)=y⟺ay=x

    where:

    • a is the base of the logarithm (a>0,a≠1)
    • y is the exponent / power
    • x is the number / argument (x>0)
  2. Identify the base, exponent, and argument from the given equation.

    Given equation:

    5=log10⁡(100000)orlog10⁡(100000)=5

    Comparing with loga⁡(x)=y:

    • Base (a): 10
    • Exponent (y): 5
    • Argument (x): 100000
  3. Write in exponential form (ay=x).

    Substituting the identified values into ay=x:

    105=100000

    (Verification: 105=10×10×10×10×10=100000.)

Answer

105=100000

Q2Part (viii)

EasyApproved by Miss Aniya • Aug 22, 2026

log4⁡(116)=−2

Hint

Base is 4, exponent is −2, and value is 116.

Solution

  1. State the conversion rule.

    loga⁡x=y⟺ay=x
  2. Identify components.

    • Base a=4
    • Exponent y=−2
    • Value x=116
  3. Write in exponential form.

    4−2=116

Answer

4−2=116

Q3Question 3

Medium

Find the value of x in each of the following:

Q3Part (i)

EasyApproved by Miss Aniya • Aug 22, 2026

logx⁡64=3

Hint

Convert to exponential form: x3=64. Then express 64=43.

Solution

  1. Convert to exponential form.

    logx⁡64=3x3=64
  2. Express 64 as a cube power.

    x3=43
  3. Equate the bases since powers are equal.

    x=4

Answer

x=4

Q3Part (ii)

EasyApproved by Miss Aniya • Aug 22, 2026

log5⁡1=x

Hint

Convert to exponential form: 5x=1. Recall that 50=1.

Solution

  1. Convert to exponential form.

    log5⁡1=x5x=1
  2. Express 1 as a power of base 5.

    5x=50
  3. Equate exponents.

    x=0

Answer

x=0

Q3Part (iii)

EasyApproved by Miss Aniya • Aug 22, 2026

logx⁡8=1

Hint

Convert to exponential form: x1=8.

Solution

Convert to exponential form.

logx⁡8=1x1=8x=8

Answer

x=8

Q3Part (iv)

MediumApproved by Miss Aniya • Aug 22, 2026

log10⁡x=−3

Hint

Convert to exponential form: x=10−3=11000.

Solution

  1. Convert to exponential form.

    log10⁡x=−3x=10−3
  2. Simplify negative power.

    x=1103x=11000(or 0.001)

Answer

x=11000orx=0.001

Q3Part (v)

MediumApproved by Miss Aniya • Aug 22, 2026

log4⁡x=32

Hint

Convert to exponential form: x=432=(22)32=23=8.

Solution

  1. Convert to exponential form.

    log4⁡x=32x=432
  2. Simplify the rational exponent.

    x=(22)32x=22×32x=23x=8

Answer

x=8

Q3Part (vi)

MediumApproved by Miss Aniya • Aug 22, 2026

log2⁡1024=x

Hint

Convert to exponential form: 2x=1024. Express 1024=210.

Solution

  1. Convert to exponential form.

    log2⁡1024=x2x=1024
  2. Factorize 1024 into base 2.

    1024=210
  3. Equate exponents.

    2x=210x=10

Answer

x=10

The exercises and question numbering reproduced on these pages are from Mathematics for Class 9 (National Curriculum of Pakistan 2023), published by the Punjab Curriculum and Textbook Board (PCTB), Lahore, authored by Muhammad Akhtar Shirani, Madiha Mahmood, and Ghulam Murtaza. PCTB holds the copyright in the original textbook. PrepSure is not affiliated with, endorsed by, or sponsored by PCTB. The worked solutions, explanations, hints and method notes are PrepSure's own original work, written and reviewed by our team. If you hold rights in this material and believe anything here exceeds fair use, write to us and we will take it down.

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