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Arithmetic Progression
In an A.P., a = 3, d = 6, n = 9, find T9:
Correct answer: B
Explanation and memory cue
The nth term of an arithmetic progression (A.P.) is given by Tn = a + (n-1)d. Here, a = 3, d = 6, and n = 9, so T9 = 3 + (9-1)*6 = 3 + 48 = 51.