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1291
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Hcf And Lcm
easy
Mathematics
The L.C.M of two numbers is 48. The numbers are in the ratio 2:3. The sum of the numbers is ___________?
A
28
B
32
C
40
D
64
Explanation and memory cue
Given the ratio 2:3, let the numbers be 2x and 3x. Their LCM is 48. The LCM of 2x and 3x is 6x, so 6x = 48, giving x = 8. Therefore, the numbers are 16 and 24, and their sum is 40.
1292
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LCM
medium
Mathematics
Find the lowest common multiple of 24, 36, and 40.
A
120
B
240
C
360
D
480
Explanation and memory cue
The lowest common multiple (LCM) of 24, 36, and 40 is 360. This is found by taking the highest powers of prime factors from each number: 24 = 2^3 * 3, 36 = 2^2 * 3^2, 40 = 2^3 * 5. The LCM is 2^3 * 3^2 * 5 = 8 * 9 * 5 = 360. Since 360 is divisible by 24, 36, and 40, it is the correct LCM.
1293
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Cylinder & Sphere
medium
Mathematics
The radius of a circular cylinder is the same as that of a sphere. Their volumes are equal. The height of the cylinder is___________?
A
4/3 times its radius
B
2/3 times its radius
C
Equal to its radius
D
Equal to its diameter
Explanation and memory cue
The volume of a sphere is (4/3)πr³ and the volume of a cylinder is πr²h. Given equal volumes and the same radius, equate (4/3)πr³ = πr²h, which simplifies to h = 4/3 r. Thus, the height of the cylinder is 4/3 times its radius.
1294
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Perimeter & Revolutions
medium
Mathematics
Find the length of the wire required to go 15 times around a square field containing 69696 m².
A
15840 m
B
16840 m
C
15820 m
D
15640 m
Explanation and memory cue
The side length of the square field is the square root of 69696 m², which is 264 m. The perimeter of the square is 4 × 264 = 1056 m. The wire goes around the field 15 times, so the total length required is 15 × 1056 = 15840 m, which corresponds to option A.
1295
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Cylinder & Cone (Ratio)
easy
Mathematics
A right cylinder and a right circular cone have the same radius and the same volume. What is the ratio of the height of the cylinder to that of the cone?
A
3:5
B
2:5
C
3:1
D
1:3
Explanation and memory cue
The volume of a cylinder is V = πr²h_cylinder, and the volume of a cone is V = (1/3)πr²h_cone. Given equal volumes and equal radii, πr²h_cylinder = (1/3)πr²h_cone, which simplifies to h_cylinder = (1/3)h_cone. Therefore, the ratio of the height of the cylinder to that of the cone is 1:3.
1296
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Remainder/Gcd
medium
Mathematics
Find the greatest number which, when dividing 19, 83, and 67, leaves a remainder of 3 in each case.
A
16
B
17
C
18
D
19
Explanation and memory cue
To find the greatest number that leaves a remainder of 3 when dividing 19, 83, and 67, subtract 3 from each number: 16, 80, and 64. The greatest number dividing all three is the GCD of 16, 80, and 64, which is 16. Hence, 16 is the required number.
1297
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Divisibility And Remainders
medium
Mathematics
Find the lowest 4-digit number which, when divided by 3, 4, or 5, leaves a remainder of 2 in each case.
A
1020
B
1026
C
1030
D
1022
Explanation and memory cue
The number must leave a remainder of 2 when divided by 3, 4, and 5. This means the number minus 2 is divisible by 3, 4, and 5. The least common multiple (LCM) of 3, 4, and 5 is 60, so the number minus 2 must be a multiple of 60. The smallest 4-digit number is 1000, so we find the smallest multiple of 60 greater than or equal to 998 (1000 - 2). 60 × 17 = 1020, so the number is 1020 + 2 = 1022. However, 1022 leaves remainder 2 when divided by 3 and 4, but not by 5. Checking 1026: 1026 - 2 = 1024, which is not divisible by 60. Checking 1020: 1020 - 2 = 1018, not divisible by 60. Checking 1022: 1022 - 2 = 1020, which is divisible by 60. Therefore, 1022 is the correct answer. Rechecking the calculations shows 1022 mod 5 = 1022 - (5 × 204) = 1022 - 1020 = 2, so 1022 leaves remainder 2 when divided by 5 as well. Therefore, the original correct answer D (1022) is correct. The initial explanation was missing, so this detailed explanation clarifies the reasoning.
1298
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Cube Surface Area (Algebraic)
easy
Mathematics
The edge of a cube is 2a cm. Find its surface area.
A
6a² cm²
B
8a² cm²
C
12a² cm²
D
24a² cm²
Explanation and memory cue
The surface area of a cube is given by 6 times the square of its edge length. Here, the edge length is 2a, so the surface area is 6 × (2a)² = 6 × 4a² = 24a² cm². The correct option is D, which matches 24a² cm².
1299
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Hcf And Lcm
medium
Mathematics
The H.C.F and L.C.M of two numbers are 21 and 84 respectively. If the ratio of the two numbers is 1:4, then the larger of the two numbers is ___________?
A
12
B
48
C
84
D
108
Explanation and memory cue
The product of two numbers equals the product of their H.C.F and L.C.M, i.e., 84 × 21 = 1764. Given the ratio 1:4, let the numbers be x and 4x. Then x × 4x = 1764, so 4x² = 1764, giving x² = 441 and x = 21. The larger number is 4x = 84. This is consistent since the H.C.F (21) is less than the L.C.M (84). Therefore, the larger number is 84, which corresponds to option C.
1300
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Spheres (Shots)
medium
Mathematics
How many shots of 1 cm radius can be prepared from a sphere of 3 cm radius?
A
36
B
64
C
27
D
16
Explanation and memory cue
The volume of the large sphere is (4/3)π(3^3) = 36π cm³. The volume of each small sphere (shot) is (4/3)π(1^3) = (4/3)π cm³. Dividing the large volume by the small volume gives 36π ÷ (4/3)π = 36 × (3/4) = 27 shots.