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Mathematics

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1341

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Cuboid Diagonal

easy
Mathematics

The edges of a cuboid are respectively 3 cm, 4 cm, and 12 cm. Find the length of the diagonal of the cuboid.

A
5 cm
B
19 cm
C
13 cm
D
144 cm
Explanation and memory cue

The length of the diagonal of a cuboid with edges 3 cm, 4 cm, and 12 cm is found using the formula cm. Therefore, the correct answer is 13 cm, which corresponds to option C, not B.

1342

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Cuboid Volume

easy
Mathematics

The edges of a cuboid are 4 cm, 5 cm, and 6 cm. Find the volume of the cuboid.

A
120 cm³
B
120 cm²
C
148 cm²
D
15 cm³
Explanation and memory cue

The volume of a cuboid is calculated by multiplying its length, width, and height. Here, 4 cm × 5 cm × 6 cm = 120 cm³, so the correct answer is 120 cm³.

1343

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Fractions

easy
Mathematics

Which of the following fractions is the largest?

A
7/8
B
13/16
C
31/40
D
63/80
Explanation and memory cue

7/8 equals 0.875, which is larger than 13/16 (0.8125), 31/40 (0.775), and 63/80 (0.7875). Therefore, 7/8 is the largest fraction among the options.

1344

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Spheres (Volume)

easy
Mathematics

The ratio between the radii of two spheres is 1:3. Find the ratio between their volumes.

A
27:1
B
1:27
C
1:9
D
9:1
Explanation and memory cue

The volume of a sphere is proportional to the cube of its radius. Given the ratio of radii is 1:3, the ratio of volumes is 1³:3³ = 1:27.

1345

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Cubes (Ratio)

easy
Mathematics

If the volumes of two cubes are in the ratio 8:1, what is the ratio of their edges?

A
8:1
B
2√2 : 1
C
2 : 1
D
None of these
Explanation and memory cue

The volume of a cube is proportional to the cube of its edge length. Given the volume ratio is 8:1, the edge length ratio is the cube root of 8:1, which is 2:1.

1346

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Box Packing

easy
Mathematics

If in a box of dimensions 6 m × 5 m × 4 m, smaller boxes of dimensions 60 cm × 50 cm × 40 cm are kept in it, then what will be the maximum number of small boxes that can be kept in it?

A
500
B
1000
C
900
D
600
Explanation and memory cue

First, convert the dimensions of the large box to centimeters: 6 m = 600 cm, 5 m = 500 cm, and 4 m = 400 cm. Then, divide each dimension by the corresponding small box dimension: 600/60 = 10, 500/50 = 10, and 400/40 = 10. Multiplying these gives 10 * 10 * 10 = 1000 small boxes that can fit inside the large box.

1347

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Cylinder Surface Area

easy
Mathematics

The radius of a cylindrical vessel is 7 cm and its height is 3 cm. Find the total surface area of the cylinder.

A
308 sq cm
B
220 sq cm
C
440 sq cm
D
132 sq cm
Explanation and memory cue

The total surface area (TSA) of a cylinder is calculated using the formula TSA = 2πr(r + h), where r is the radius and h is the height. Given r = 7 cm and h = 3 cm, substituting these values gives TSA = 2 × π × 7 × (7 + 3) = 2 × π × 7 × 10 = 140π ≈ 439.6 sq cm. Among the options provided, 440 sq cm (option C) is the closest to the calculated value. Therefore, the correct answer is C.

1348

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Cubes (Volume)

medium
Mathematics

Three cubes of metal whose edges are 9 cm, 12 cm, and 15 cm respectively, are melted and one new cube is made. Find the edge length of the new cube.

A
21 cm
B
19 cm
C
32 cm
D
18 cm
Explanation and memory cue

The volumes of the three cubes are calculated as 9³ = 729 cm³, 12³ = 1728 cm³, and 15³ = 3375 cm³. Adding these volumes gives a total volume of 729 + 1728 + 3375 = 5832 cm³. When these three cubes are melted and recast into one cube, the volume of the new cube is 5832 cm³. The edge length of the new cube is the cube root of 5832, which is exactly 18 cm. Therefore, the correct answer is option D (18 cm).

1349

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Hcf And Lcm

easy
Mathematics

Three numbers are in the ratio 1:2:3 and their H.C.F is 12. The numbers are___________?

A
4, 8, 12
B
5, 10, 15
C
10, 20, 30
D
12, 24, 36
Explanation and memory cue

The numbers are in the ratio 1:2:3, so let the numbers be 12x, 24x, and 36x. Since their H.C.F is 12, the common factor x must be 1. Therefore, the numbers are 12, 24, and 36.

1350

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Surface Area & Cost

easy
Mathematics

A room is 15 m long, 4 m broad, and 3 m high. Find the cost of whitewashing its four walls at 50 paise per m².

A
Rs.60
B
Rs.57
C
Rs.55
D
Rs.52
Explanation and memory cue

The area of the four walls of a rectangular room is calculated using the formula: Area = 2 × height × (length + breadth). Here, length = 15 m, breadth = 4 m, and height = 3 m. So, the area = 2 × 3 × (15 + 4) = 2 × 3 × 19 = 114 m². The cost of whitewashing is given as 50 paise per m², which is Rs. 0.5 per m². Therefore, the total cost = 114 × 0.5 = Rs. 57. Hence, the correct answer is Rs. 57, which corresponds to option B.