PrepSure LogoHubPage 156/182
Normal Study1,815 questions

Mathematics

Scan verified MCQs with the answer highlighted, then open explanations when you want the reasoning.

Deep Study Mode
Showing 1551-1560 of 1815Use Deep Study when you want one-question focus.
1551

Read Mode

Circle Sector (Perimeter)

medium
Mathematics

The sector of a circle has a radius of 21 cm and a central angle of 135°. Find its perimeter.

A
91.5 cm
B
93.5 cm
C
94.5 cm
D
92.5 cm
Explanation and memory cue

The perimeter of a sector of a circle is calculated as the sum of the lengths of the two radii and the arc length. The arc length is given by (central angle/360) × 2π × radius. For a radius of 21 cm and a central angle of 135°, the arc length = (135/360) × 2π × 21 = 49.5 cm (using π ≈ 22/7). Adding the two radii (2 × 21 = 42 cm) gives the perimeter = 42 + 49.5 = 91.5 cm. This matches option A, so the correct answer is A.

1552

Read Mode

Equilateral Triangle Area

easy
Mathematics

What is the area of an equilateral triangle with side 16 cm?

A
48√3 cm²
B
128√3 cm²
C
9.6√3 cm²
D
64√3 cm²
Explanation and memory cue

The area of an equilateral triangle is given by the formula (√3 / 4) × side². For side 16 cm, area = (√3 / 4) × 16² = (√3 / 4) × 256 = 64√3 cm². However, option B is 128√3 cm², which is double the correct area. The correct area matches option D, 64√3 cm², so the original correct_answer 'D' is correct. The explanation was missing and has been added. The question text had a typo 'are' instead of 'area', which has been corrected.

1553

Read Mode

Average (Before/After Joining)

easy
Mathematics

The average amount with a group of seven numbers is Rs. 20. If the newly joined member has Rs. 50 with him, what was the average amount with the group before his joining the group?

A
Rs. 25
B
Rs. 15
C
Rs. 18
D
Rs. 22
Explanation and memory cue

The total amount after the new member joins is 7 × 20 = Rs. 140. The new member contributes Rs. 50, so the total amount before joining was 140 - 50 = Rs. 90. Since there were 6 members before, the average before joining is 90 ÷ 6 = Rs. 15.

1554

Read Mode

Ages & Averages

medium
Mathematics

The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?

A
23 years
B
24 years
C
25 years
D
None of these
Explanation and memory cue

Let the average age of the whole team be x years. The total age of the team is 11x. The captain is 26 years old, and the wicket keeper is 29 years old (3 years older). Excluding these two, the sum of the remaining 9 players' ages is 11x - 26 - 29 = 11x - 55. The average age of these 9 players is (11x - 55)/9, which is given as one year less than the whole team's average, so (11x - 55)/9 = x - 1. Solving this equation gives x = 24 years.

1555

Read Mode

Area & Cost (Walls, Door, Windows)

medium
Mathematics

The dimensions of a room are 25 feet × 15 feet × 12 feet. What is the cost of whitewashing the four walls of the room at Rs. 5 per square foot if there is one door of dimensions 6 feet × 3 feet and three windows of dimensions 4 feet × 3 feet each?

A
Rs. 4800
B
Rs. 3600
C
Rs. 3560
D
Rs. 4530
Explanation and memory cue

The total area of the four walls is 2 × height × (length + breadth) = 2 × 12 × (25 + 15) = 960 sq ft. The area of the door is 6 × 3 = 18 sq ft, and the total area of the three windows is 3 × (4 × 3) = 36 sq ft. The net area to be whitewashed is 960 - (18 + 36) = 906 sq ft. At Rs. 5 per sq ft, the cost is 906 × 5 = Rs. 4530. However, the correct calculation shows the cost as Rs. 4530, which matches option D, so the original correct answer is correct. Rechecking the calculation: 2 × 12 × (25 + 15) = 2 × 12 × 40 = 960 sq ft; subtract door and windows area (18 + 36 = 54), net area = 906 sq ft; cost = 906 × 5 = Rs. 4530. Therefore, option D is correct.

1556

Read Mode

Wheels & Circumference

easy
Mathematics

The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 500 revolutions?

A
252 m
B
704 m
C
352 m
D
808 m
Explanation and memory cue

The distance covered by the wheel is the circumference multiplied by the number of revolutions. Circumference = 2 × π × radius = 2 × 3.14 × 22.4 cm = 140.4 cm = 1.404 m. Distance = 1.404 m × 500 = 702 m approximately. However, the closest option to this calculation is 704 m (option B). On rechecking, the radius is 22.4 cm, so circumference = 2 × π × 22.4 = 140.5 cm or 1.405 m. Distance = 1.405 × 500 = 702.5 m, which matches option B (704 m) closely. Therefore, the original correct answer B is correct. The initial calculation error was due to rounding. The correct answer is B.

1557

Read Mode

Mean & Correction

medium
Mathematics

The mean marks of 30 students in a class is 58.5. Later on, it was found that 75 was wrongly recorded as 57. Find the correct mean.

A
57.4
B
57.5
C
58.9
D
59.1
Explanation and memory cue

The original total marks for 30 students is 30 × 58.5 = 1755. The incorrect mark recorded was 57 instead of 75, so the total should be corrected by adding (75 - 57) = 18. The corrected total is 1755 + 18 = 1773. The corrected mean is 1773 ÷ 30 = 59.1.

1558

Read Mode

Speed/Rate (Run Rate)

medium
Mathematics

In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?

A
6.25
B
6.5
C
6.75
D
7
Explanation and memory cue

The run rate is calculated by dividing the total runs scored by the number of overs faced. In the first 10 overs, the run rate was 3.2, so runs scored = 3.2 × 10 = 32 runs. The target is 282 runs, so remaining runs needed = 282 - 32 = 250 runs. The remaining overs are 40. Therefore, the required run rate for the remaining overs = 250 ÷ 40 = 6.25 runs per over. This corresponds to option A.

1559

Read Mode

Average & Number Sets

medium
Mathematics

The average of four positive integers is 69. The highest integer is 93 and the least integer is 39. The difference between the remaining two integers is 28. Which of the following integers is the higher of the remaining two integers?

A
58
B
86
C
49
D
None of these
Explanation and memory cue

The total sum of the four integers is 69 × 4 = 276. Given the highest integer is 93 and the least is 39, their sum is 132. The remaining two integers sum to 276 - 132 = 144, and their difference is 28. Let the two integers be x and y, with x > y. Then x + y = 144 and x - y = 28. Adding these gives 2x = 172, so x = 86. However, 86 is not among the options except B, but option B is 86. Wait, the options are A:58, B:86, C:49, D:None of these. So the higher integer is 86, which is option B. The original correct_answer is B, which is correct. The explanation was missing, so it is added now. Difficulty is medium due to algebraic reasoning required. Tags added accordingly.

1560

Read Mode

Arithmetic Mean Change

easy
Mathematics

If the arithmetic mean of seventy-five numbers is 35, what is the mean of the new numbers if each number is increased by 5?

A
30
B
40
C
70
D
90
Explanation and memory cue

When each number is increased by 5, the mean also increases by 5. Since the original mean is 35, the new mean will be 35 + 5 = 40.