Mathematics

Given the perimeters of two squares as 48 cm and 20 cm, their side lengths are 48/4 = 12 cm and 20/4 = 5 cm respectively. Their areas are 12² = 144 cm² and 5² = 25 cm², so the combined area is 169 cm². The side length of the new square with area 169 cm² is √169 = 13 cm. The perimeter of this new square is 4 × 13 = 52 cm, and its diagonal is side × √2 = 13√2 cm. Since the options only list diagonal lengths, the correct answer is the diagonal 13√2 cm, which corresponds to option B. The original answer marked as C (16√2 cm) is incorrect.

The surface area of a rectangular brick is calculated by 2(lw + lh + wh). For dimensions 10cm, 4cm, and 3cm, the surface area is 2(10*4 + 10*3 + 4*3) = 2(40 + 30 + 12) = 2(82) = 164 cm². However, the options given show 124 Sq.cm as option B, which is incorrect. Recalculating carefully: 2(10*4 + 10*3 + 4*3) = 2(40 + 30 + 12) = 2(82) = 164 Sq.cm, so option C is correct. The initial explanation was missing, so it is added now.

Given the area of the circle is 616 sq cm, use the formula for area A = πr² to find the radius: r = √(A/π) = √(616/3.14) ≈ 14 cm. Then, calculate the circumference C = 2πr ≈ 2 × 3.14 × 14 ≈ 87.92 cm, which rounds to 88 cm. Therefore, the correct circumference is approximately 88 cm, matching option B.

The area of the two roads is calculated by adding the area of each road and subtracting the overlapping square area where they intersect. The road parallel to length: 80 m × 10 m = 800 m²; road parallel to breadth: 60 m × 10 m = 600 m²; overlapping area: 10 m × 10 m = 100 m². Total road area = 800 + 600 - 100 = 1300 m². Cost = 1300 × Rs.3 = Rs.3900. However, the calculation shows Rs.3900, which corresponds to option D, so the original correct answer D is correct. The explanation clarifies the calculation steps.

The additional grassy ground grazed is the difference between the areas of two circles with radii 23 m and 12 m. The area difference = π(23² - 12²) = π(529 - 144) = π(385) ≈ 3.1416 × 385 ≈ 1209.6 m², which rounds to 1210 m². Therefore, the correct answer is option C (1210 m²), not A (1120 m²).

The original plot's area is 4320 sq.m. Dividing it into 3 square plots along the shorter side and then 3 more along the longer side with no leftover area implies that the sides are multiples of the square plot's side lengths. Option C (120m × 36m) fits these conditions, as 120/3 = 40m and 36/3 = 12m, both integers, allowing square plots of 40m and 12m sides respectively, covering the entire area without surplus.

The area of a triangle is calculated using the formula (1/2) × base × height. With a base of 4 m and height of 5 m, the area is (1/2) × 4 × 5 = 10 square meters.

The perimeter of a semicircle is calculated by adding the diameter and the half circumference of the circle. The diameter is 2 × radius = 2 × 6.3 = 12.6 cm. The half circumference is π × radius ≈ 3.14 × 6.3 ≈ 19.79 cm. Adding these gives the perimeter ≈ 12.6 + 19.79 = 32.39 cm, which rounds to 32.4 cm. Therefore, option B is correct.

If the length is increased by 60%, the new length is 1.6 times the original. To keep the area the same, the width must be multiplied by 1/1.6 = 0.625, which is a 37.5% decrease.

Let the shorter side be x meters and the longer side be y meters. Given area xy = 60 and the diagonal d and longer side y satisfy d + y = 5x. Using Pythagoras, d = sqrt(x^2 + y^2). Substituting y = 60/x and d = sqrt(x^2 + (60/x)^2), the equation becomes sqrt(x^2 + (60/x)^2) + 60/x = 5x. Solving this yields x = 5, so the shorter side is 5 m and the longer side y = 60/5 = 12 m. The question asks for the length (longer side), which is 12 m, but the options label 5 m as A and 12 m as B. Since the question asks for the length (longer side), the correct answer is B (12 m). However, the original correct_answer was B, which matches 12 m, so it is correct. The explanation was missing and has been added. The question text was corrected for grammar and clarity, and topic and difficulty were added.

Let the width of the rectangular field be x meters. Then the length is 2x meters. The area of the field is length × width = 2x × x = 2x². The pond is a square with side length 8 m, so its area is 8 × 8 = 64 m². Given that the pond's area is 1/8 of the field's area, we have 64 = (1/8) × 2x². Simplifying, 64 = (1/4) x², so x² = 256, and x = 16 m. Therefore, the length of the field is 2x = 2 × 16 = 32 m. This matches option B.

Using the sides of the parallelogram (60 m and 40 m) and one diagonal (80 m), we apply the formula for the diagonal: d² = a² + b² - 2ab cosθ. Solving for cosθ and then sinθ, the area = ab sinθ = 320 sq.m.

Let the length of the side parallel to the uncovered side be x feet. The uncovered side is 20 feet, so the area is x × 20 = 680, giving x = 34 feet. The fencing is required for three sides: two lengths of 34 feet and one side of 20 feet, totaling 34 + 34 + 20 = 88 feet.

When the length is increased by 10%, it becomes 1.10 times the original. When the breadth is increased by 25%, it becomes 1.25 times the original. The new area is 1.10 × 1.25 = 1.375 times the original area, which is a 37.5% increase.

The floor dimensions are 4 m by 9 m, but with a 0.25 m space around, the effective area to be tiled is (4 - 2*0.25) m by (9 - 2*0.25) m = 3.5 m by 8.5 m. Converting to centimeters, this is 350 cm by 850 cm. Each tile is 25 cm by 25 cm, so the number of tiles needed is (350/25) * (850/25) = 14 * 34 = 476. However, since the question asks for the number of tiles to cover the floor leaving the space around, the actual tiled area is smaller, so the correct calculation is for the inner area, which is 3.5 m by 8.5 m, resulting in 476 tiles. Therefore, option B (476) is correct.

To find the maximum length of a square tile that can fill the floor without cutting, we need to find the greatest common divisor (GCD) of the room's length and width. The length is 12 ¼ m (12.25 m) and the width is 7 m. Converting to centimeters: 1225 cm and 700 cm. The GCD of 1225 and 700 is 35 cm. Therefore, the maximum length of the square tile that can fill the floor with a whole number of tiles is 35 cm. Among the given options, 175 cm is not the GCD, and 150 cm is not a divisor of both dimensions. The correct maximum tile size is 35 cm, but since 35 cm is not listed in the options, the closest correct answer based on the GCD calculation is 175 cm (option B). However, the actual GCD is 35 cm, so the question options are incorrect. The correct answer should be 35 cm, but since it is not an option, the best choice is option B (175 cm) if considering the original question's intent. The original correct answer D (150 cm) is incorrect.

The area of an equilateral triangle is given by (√3/4) × side². Setting this equal to 4√3 and solving for the side length gives side = 3 cm.

The circumference of the original circular wire is calculated as 2πr = 2 × (22/7) × 42 = 264 cm. When the wire is bent into a rectangle with sides in the ratio 6:5, let the sides be 6x and 5x. The perimeter of the rectangle is 2(6x + 5x) = 22x, which equals the circumference of the circle, 264 cm. Solving 22x = 264 gives x = 12 cm. Therefore, the smaller side is 5x = 5 × 12 = 60 cm. Hence, the correct answer is option B (60 cm).

Since AB and AC are equal chords of length 6 cm in a circle of radius 5 cm, triangle ABC is isosceles with AB = AC = 6 cm. Using the circle's radius and chord length, the distance from the center to the chord can be found, and then applying the Law of Cosines or coordinate geometry, the length of chord BC is calculated as 12/5 cm.

The perimeter P of a rectangle is given by P = 2(length + breadth). Given P = 600 m and breadth = 100 m, we have 600 = 2(length + 100), so length + 100 = 300, thus length = 200 m. However, the correct calculation is length = 200 m, which corresponds to option C. Therefore, option C is correct, not D.

The area of a rhombus is half the product of its diagonals. Here, area = (1/2) × 15 cm × 20 cm = 150 cm². The correct unit is square centimeters, not square meters.

Let the breadth be x meters. Then the length is (4/3)x meters. The area is length × breadth = (4/3)x × x = (4/3)x² = 300. Solving for x² gives x² = 225, so x = 15 meters (breadth). Length = (4/3) × 15 = 20 meters. The difference between length and breadth is 20 - 15 = 5 meters. Since 5 meters is not among the given options (15m, 4m, 3m), the correct choice is 'None of these'.

The volume of earth dug from the drain equals the volume spread over the plot. Calculating the volume of the drain (outer rectangle minus inner rectangle times depth) and equating it to the volume increase on the plot (area times height increase) gives the drain depth as approximately 1.225 m, matching option B.

The circumference of a circular wheel is given by the formula C = 2πr. For a wheel with radius r = 1.75 m, the circumference is C = 2 × π × 1.75 ≈ 11.0 m. To travel a distance of 1 km (1000 m), the number of revolutions the wheel makes is the total distance divided by the circumference: 1000 ÷ 11.0 ≈ 90.9 revolutions, which rounds to about 91 revolutions. Among the given options, 90 (option A) is the closest to this calculated value. Therefore, the correct answer is A.

When the side of a square is increased by 25%, the new side length is 1.25 times the original. The area increases by (1.25)^2 - 1 = 1.5625 - 1 = 0.5625, or 56.25%.