Read Mode
Combinatorics
A committee has 5 men and 6 women. What is the number of ways to select 2 men and 3 women from the given committee?
Explanation and memory cue
The number of ways to select 2 men from 5 is C(5,2) = 10, and the number of ways to select 3 women from 6 is C(6,3) = 20. Multiplying these gives 10 × 20 = 200 ways. However, the options given do not include 200 as the correct answer; option B is 200 but the calculation shows 10 × 20 = 200, so the correct answer is B, not D. Rechecking: C(5,2) = 10, C(6,3) = 20, total = 200, so correct answer is B.